![If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) ( If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (](https://d10lpgp6xz60nq.cloudfront.net/ss/web/129553.jpg)
If a^2+b^2+c^2+ab+bc+ca<=0 AA a, b, c in R then find the value of the determinant |[(a+b+2)^2, a^2+b^2, 1] , [1, (b+c+2)^2, b^2+c^2] , [c^2+a^2, 1, (c+a+2)^2]| : (A) abc(a^2 + b^2 +c^2) (
![radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange](https://i.stack.imgur.com/UVS3U.png)
radicals - Use the Cauchy-Schwarz Inequality to prove that $a^2+b^2+c^2 \ge ab+ac+bc $ for all positive $a,b,c$. - Mathematics Stack Exchange
![Simplify: `(a^2 - (b-c)^2)/((a+c)^2 - b^2) + (b^2 - (a-c)^2)/((a+b)^2 - c^2) + (c^2 - (a-b)^2)... - YouTube Simplify: `(a^2 - (b-c)^2)/((a+c)^2 - b^2) + (b^2 - (a-c)^2)/((a+b)^2 - c^2) + (c^2 - (a-b)^2)... - YouTube](https://i.ytimg.com/vi/_5rvzXmlfRk/maxresdefault.jpg)
Simplify: `(a^2 - (b-c)^2)/((a+c)^2 - b^2) + (b^2 - (a-c)^2)/((a+b)^2 - c^2) + (c^2 - (a-b)^2)... - YouTube
![matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange](https://i.stack.imgur.com/dPZKQ.jpg)
matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange
![if a+b+c=8, a2+b2+c2=30,find the value of ab+bc+ca - Maths - Polynomials - 4662937 | Meritnation.com if a+b+c=8, a2+b2+c2=30,find the value of ab+bc+ca - Maths - Polynomials - 4662937 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/discuss_editlive/3781436/2013_04_29_12_46_05/mathmlequation7523069594225382366.png)
if a+b+c=8, a2+b2+c2=30,find the value of ab+bc+ca - Maths - Polynomials - 4662937 | Meritnation.com
Using properties of determinants, prove that |(a,b,c)(a2,b2,c2)(bc,ca,ca)| = (a-b)(b-c)(c-a)(ab+bc+ca) - Sarthaks eConnect | Largest Online Education Community
How to prove [math]a^2+b^2+c^2-ab-bc-ca[/math] is non-negative for all values of [math] a, b,[/math] and [math]c - Quora
![If the roots of the equation (c2–ab)x2–2(a2–bc)x + b2–ac = 0 are equal, prove that either a = 0 or a3+ - Brainly.in If the roots of the equation (c2–ab)x2–2(a2–bc)x + b2–ac = 0 are equal, prove that either a = 0 or a3+ - Brainly.in](https://hi-static.z-dn.net/files/d45/6b1403303834b59179f3cb94266e0647.jpg)
If the roots of the equation (c2–ab)x2–2(a2–bc)x + b2–ac = 0 are equal, prove that either a = 0 or a3+ - Brainly.in
![a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube](https://i.ytimg.com/vi/qZ4f3NzbS6Y/maxresdefault.jpg)
a-b)^3 + (b-c)^3 + (c-a)^3=?` (a)`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)` (b)`3(a-b)( b-c)(c-a)` (c)`( - YouTube
![matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange matrices - Prove that the determinant is $(a-b)(b-c)(c-a)(a^2 + b^2 + c^2 )$ - Mathematics Stack Exchange](https://i.stack.imgur.com/WqPIX.jpg)